Time between button presses - Raspberry Pi Forums

i'm trying code in way of measuring time between presses of switch , stop process if time exceeds set amount.

have automated cycle testing rig set now. cycles thread in , out using stepper motor should take around 40 seconds complete cycle. controlled limit switches @ either end , should return first limit switch within 40 seconds.
should fail return within 40 seconds approx, signifying failure of testing, want kill program , print failure warning.

whats best method this?
thanks!

code: select all

from time import sleep import time import rpi.gpio gpio   dir = 20   # direction gpio pin step = 21  # step gpio pin cw = 1     # clockwise rotation ccw = 0    # counterclockwise rotation spr = 18400   # steps per revolution (360 / 0.067 * 3.5) switch27 = 27 switch13 = 13 cycle_count = 5 number = 0    gpio.setwarnings(false) gpio.setmode(gpio.bcm) gpio.setup(27, gpio.in, pull_up_down=gpio.pud_up) gpio.setup(13, gpio.in, pull_up_down=gpio.pud_up) gpio.setup(5, gpio.in, pull_up_down=gpio.pud_up) gpio.setup(dir, gpio.out) gpio.setup(step, gpio.out) gpio.output(dir, ccw)  mode = (14, 15, 18)   # microstep resolution gpio pins gpio.setup(mode, gpio.out) resolution = {'full': (0, 0, 0),               'half': (1, 0, 0),               '1/4': (0, 1, 0),               '1/8': (1, 1, 0),               '1/16': (0, 0, 1),               '1/32': (1, 0, 1)} gpio.output(mode, resolution['full'])  step_count = spr delay = .0004     while true:     input_value = gpio.input(5)  #set rear switch      if input_value == false:         number += 1         print ('cycle count', (number))         sleep(6)        while 1:     gpio.output(dir, ccw)     x in range(step_count):         gpio.output(step, gpio.high)         sleep(delay)         gpio.output(step, gpio.low)         sleep(delay)         input_state1 = gpio.input(13)         if input_state1 == true:             break     sleep(2)     gpio.output(dir, cw)     x in range(step_count):         gpio.output(step, gpio.high)         sleep(delay)         gpio.output(step, gpio.low)         sleep(delay)         input_state2 = gpio.input(27)         if input_state1 == true:             break            gpio.cleanup() 

take @ apscheduler http://apscheduler.readthedocs.io/en/la ... -trigger-s, background scheduler.

can create background scheduler, , if 1 of limit switches fires, can reschedule job refresh timeout timer. if timeout occurs, gracefully exit program.

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